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Speech Module solution in Clear category for Speech Module by booratello
def checkio(number):
std_num_dict = {1: "one", 2: "two", 3: "three", 4: "four", 5: "five",
6: "six", 7: "seven", 8: "eight", 9: "nine", 10: "ten",
11: "eleven", 12: "twelve", 13: "thirteen", 14: "fourteen"}
# I wanted to limit the dictionary to 12, but then an error appears in
# the number 40 as "fourty".
composite_num_dict = {2: "twen", 3: "thir", 4: "for", 5: "fif",
6: "six", 7: "seven", 8: "eigh", 9: "nine"}
hundreds = std_num_dict[number // 100] + " hundred " \
if number // 100 > 0 else ""
decades = number % 100 if number % 100 != 0 else ""
if type(decades) is int:
if decades <= 14:
decades = std_num_dict[decades]
elif 15 <= decades <= 19:
decades = composite_num_dict[decades % 10] + "teen"
else:
first_nine = std_num_dict[decades % 10] \
if decades % 10 != 0 else ""
decades = composite_num_dict[decades // 10] + "ty " \
if decades // 10 != 0 else ""
decades = decades + first_nine
return (hundreds + decades).rstrip()
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(4) == 'four', "1st example"
assert checkio(133) == 'one hundred thirty three', "2nd example"
assert checkio(12) == 'twelve', "3rd example"
assert checkio(101) == 'one hundred one', "4th example"
assert checkio(212) == 'two hundred twelve', "5th example"
assert checkio(40) == 'forty', "6th example"
assert not checkio(212).endswith(' '), "Don't forget strip whitespaces at the end of string"
print('Done! Go and Check it!')
Jan. 17, 2020
