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Split digit based solution in Clear category for Speech Module by WittyWalrus
FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
HUNDRED = "hundred"
def checkio(number):
# digits
first, second, third, *_ = list(map(int, str(number)[::-1] + '000'))
words = []
if third:
words.extend([FIRST_TEN[third - 1], HUNDRED])
if 10 <= 10*second + first <= 19:
words.append(SECOND_TEN[10*second + first - 10])
else:
if second:
words.append(OTHER_TENS[second-2])
if first:
words.append(FIRST_TEN[first - 1])
return ' '.join(words)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(4) == 'four', "1st example"
assert checkio(133) == 'one hundred thirty three', "2nd example"
assert checkio(12) == 'twelve', "3rd example"
assert checkio(101) == 'one hundred one', "4th example"
assert checkio(212) == 'two hundred twelve', "5th example"
assert checkio(40) == 'forty', "6th example"
assert not checkio(212).endswith(' '), "Don't forget strip whitespaces at the end of string"
print('Done! Go and Check it!')
July 15, 2019
