First creative solution for Spaceship Landing Strip by smilicic - python coding challenges

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First solution in Creative category for Spaceship Landing Strip by smilicic

checkio= lambda landing_map,good={'G','S'}:max((i-k+1)*(j-l+1) for i,line in enumerate(landing_map) for j,letter in enumerate(line) for k in range(i+1) for l in range(j+1) if all(lett in good for scanline in landing_map[k:i+1] for lett in scanline[l:j+1]))

Aug. 11, 2014

Comments:

veky on Aug. 11, 2014, 10:19 p.m.
<p>Nice. Trivia: set("GS") is probably nicer than {'G', 'S'}. And a bit more substantial thing: enumerate has optional second parameter. Here enumerate(...,1) would probably help. ;-)</p>

nanpa on Dec. 15, 2015, 5:54 a.m.
<p>Nanya Kore!?</p>

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