First clear solution for Spaceship Landing Strip by Tinus_Trotyl - python coding challenges

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First solution in Clear category for Spaceship Landing Strip by Tinus_Trotyl

def checkio(landing_map):
    n = [[0 if landing_map[y][x] in 'GS' else 1 \
        for x in range(len(landing_map[0]))] \
            for y in range(len(landing_map))]
    a = 0
    for y0 in range(len(n)):
        for y1 in range(y0, len(n)):
            for x0 in range(len(n[0])):
                for x1 in range(x0, len(n[0])):
                    if not sum([n[y][x] for x in range(x0, x1+1) for y in range(y0, y1+1)]):
                       a = max(a, (x1 - x0 + 1) * (y1 - y0 + 1))
    return a

Feb. 22, 2019

Comments:

ddavidse on Nov. 25, 2020, 3:33 p.m.
amazing, well done!

CDG.Axel on Jan. 30, 2022, 8:55 a.m.
Good, but awful conversion to 0-1 matrix. <pre class='brush: python'>n = [[x in 'RWT' for x in y] for y in area] </pre> And you may shorten inner comprehension using slices: <pre class='brush: python'>if sum(sum(row[x0:x1+1]) for row in n[y0:y1+1]): or without if in one line a = max(a, (x1-x0+1) * (y1-y0+1) * (not sum(sum(row[x0:x1+1]) for row in n[y0:y1+1]))) </pre> PS: you need no int conversion for sum it

Tinus_Trotyl on Feb. 6, 2022, 9:58 p.m.
I see . . . Thank you for noticing .

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