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First solution in Speedy category for Sort by Extension by cholezhao
from typing import List
def sort_by_ext(files: List[str]) -> List[str]:
# your code here
empty=sorted([c for c in files if c.startswith('.') and c.count('.')==1])
others = sorted([c for c in files if c not in empty],key=lambda x: (x.split('.')[-1],x.split('.')[0]))
return empty + others
if __name__ == '__main__':
print("Example:")
print(sort_by_ext(['1.cad', '1.bat', '1.aa']))
# These "asserts" are used for self-checking and not for an auto-testing
assert sort_by_ext(['1.cad', '1.bat', '1.aa']) == ['1.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '2.bat']) == ['1.aa', '1.bat', '2.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.bat']) == ['.bat', '1.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '.aa', '.bat']) == ['.aa', '.bat', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.', '1.aa']) == ['1.', '1.aa', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '1.aa.doc']) == ['1.aa', '1.bat', '1.cad', '1.aa.doc']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.aa.doc']) == ['1.aa', '1.bat', '1.cad', '.aa.doc']
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May 14, 2020
