filename.rpartition('.'), partial(sorted, key=...) clear solution for Sort by Extension by Phil15 - python coding challenges

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filename.rpartition('.'), partial(sorted, key=...) solution in Clear category for Sort by Extension by Phil15

from functools import partial

def _sort_by_ext_key(filename):
    name, _, ext = filename.rpartition('.')
    return (ext, name) if name else ('', ext)

sort_by_ext = partial(sorted, key=_sort_by_ext_key)

March 9, 2020

Comments:

nikita0063 on May 23, 2020, 7:15 a.m.
cool!

kudinov.feodor on June 21, 2020, 10:37 a.m.
Learned something new I can invent case, when this function fails: ``` assert sortbyext(['1.abc', 'abc', ".abc"]) == [".abc", 'abc', '1.abc'] ```

Phil15 on June 21, 2020, 12:40 p.m.
@kudinov.feodor Well, a simple fix (keep separator in "name part"): <pre class='brush: python'>def _sort_by_ext_key(filename): name, sep, ext = filename.rpartition('.') # assert sep in ('', '.') return (ext, name) if name else ('', sep + ext) </pre>

H0r4c3 on May 1, 2023, 5:17 p.m.
Advanced solution using rpartition and partial! Nice!

Phil15 on May 1, 2023, 5:39 p.m.
For me, `partial(sorted, key=...)` was just mandatory. I think the mission should have been to write the "key" function for this, then for once we would have to write a function where the return type was only up to us, I think that would have been nice. For "rpartition", I think it's the right tool for the job here, and it's the only time I used a "[r]partition" method, I was waiting to find a real use case for it, so I like it.

H0r4c3 on May 1, 2023, 6:57 p.m.
It is good to find out that Python has these possibilities. When the time will come, I will use them, too. Bookmarked!

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