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One expression with lambda solution in Speedy category for Sort by Extension by GrigorySol
from typing import List
def sort_by_ext(files: List[str]) -> List[str]:
return sorted(sorted(files), key=lambda ext: ext.split('.')[-1] \
if len(ext.split('.')[-1]) + 1 != len(ext) \
and ext[-1] != '.' else '.')
if __name__ == '__main__':
print("Example:")
print(sort_by_ext(['1.cad', '1.bat', '1.aa']))
# These "asserts" are used for self-checking and not for an auto-testing
assert sort_by_ext(['1.cad', '1.bat', '1.aa']) == ['1.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '2.bat']) == ['1.aa', '1.bat', '2.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.bat']) == ['.bat', '1.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '.aa', '.bat']) == ['.aa', '.bat', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.', '1.aa']) == ['1.', '1.aa', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '1.aa.doc']) == ['1.aa', '1.bat', '1.cad', '1.aa.doc']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.aa.doc']) == ['1.aa', '1.bat', '1.cad', '.aa.doc']
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May 12, 2020