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Second solution in Uncategorized category for Sort by Extension by Elena_Korljukova
from typing import List
def sort_by_ext(files: List[str]) -> List[str]:
return sorted(files, key = lambda x: (x.lstrip('.').split('.')[-2: ][1 :], x.lstrip('.').split('.')[-2: ][0]))
if __name__ == '__main__':
print("Example:")
print(sort_by_ext(['1.cad', '1.bat', '1.aa']))
print(sort_by_ext(['1.cad', '1.bat', '1.aa', '.bat']))
# These "asserts" are used for self-checking and not for an auto-testing
assert sort_by_ext(['1.cad', '1.bat', '1.aa']) == ['1.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '2.bat']) == ['1.aa', '1.bat', '2.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.bat']) == ['.bat', '1.aa', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '.aa', '.bat']) == ['.aa', '.bat', '1.bat', '1.cad']
assert sort_by_ext(['1.cad', '1.', '1.aa']) == ['1.', '1.aa', '1.cad']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '1.aa.doc']) == ['1.aa', '1.bat', '1.cad', '1.aa.doc']
assert sort_by_ext(['1.cad', '1.bat', '1.aa', '.aa.doc']) == ['1.aa', '1.bat', '1.cad', '.aa.doc']
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Aug. 13, 2020
