Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Sort Array by Element Frequency by m.kurapov
def frequency_sort(items):
# your code here
ret=[]
set1=set(items)
list_wcnt=[(x,items.count(x),items.index(x)) for x in set1]
sorted_list=sorted(list_wcnt,key=lambda x:(1/x[1],x[2]),reverse=False)
for e in sorted_list:
ret += [e[0] for x in range(e[1])]
return ret
if __name__ == '__main__':
print("Example:")
print(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
assert list(frequency_sort(['bob', 'bob', 'carl', 'alex', 'bob'])) == ['bob', 'bob', 'bob', 'carl', 'alex']
assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
assert list(frequency_sort([])) == []
assert list(frequency_sort([1])) == [1]
print("Coding complete? Click 'Check' to earn cool rewards!")
Dec. 8, 2019
