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First solution in Clear category for Similar Triangles by m1ddle
from typing import List, Tuple
Coords = List[Tuple[int, int]]
from itertools import combinations
def dist(a, b):
return ((a[0] - b[0]) ** 2 + (a[1] - b[1]) ** 2) ** 0.5
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
# your code here
t1 = sorted([dist(i[0], i[1]) for i in combinations(coords_1, 2)])
t2 = sorted([dist(i[0], i[1]) for i in combinations(coords_2, 2)])
t = [t1[i] / t2[i] for i in range(len(t1))]
return len(set(t)) == 1
if __name__ == '__main__':
print("Example:")
print(similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]))
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
April 27, 2021
