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First solution in Clear category for Similar Triangles by l.szyman10
from typing import List, Tuple
Coords = List[Tuple[int, int]]
def length(a,b):
return ((a[0]-b[0])**2+(a[1]-b[1])**2)**0.5
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
# your code here
len_1 = sorted([length(coords_1[0],coords_1[1]),
length(coords_1[0],coords_1[2]),
length(coords_1[1],coords_1[2])])
len_2 = sorted([length(coords_2[0],coords_2[1]),
length(coords_2[0],coords_2[2]),
length(coords_2[1],coords_2[2])])
return round(len_1[0]/len_2[0],12) == round(len_1[1]/len_2[1],12) == round(len_1[2]/len_2[2],12)
if __name__ == '__main__':
print("Example:")
print(similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]))
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
Feb. 19, 2020
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