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First solution in Clear category for Similar Triangles by freixodachamorra
from typing import List, Tuple
Coords = List[Tuple[int, int]]
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
def long (p1, p2):
return((p1[0] - p2[0]) ** 2 + (p1[1] - p2[1]) ** 2 ) ** 0.5
p1 = sorted([long(coords_1[0], coords_1[1]), long(coords_1[1], coords_1[2]), long(coords_1[0], coords_1[2])])
p2 = sorted([long(coords_2[0], coords_2[1]), long(coords_2[1], coords_2[2]), long(coords_2[0], coords_2[2])])
divs = [p1[i] / p2[i] for i in range(len(p1))]
return all([divs[0] == i for i in divs])
if __name__ == '__main__':
print("Example:")
print(similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]))
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
Feb. 15, 2020
