1-liner: 150 chars creative solution for Similar Triangles by dankiktenko - python coding challenges

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1-liner: 150 chars solution in Creative category for Similar Triangles by dankiktenko

similar_triangles=lambda*t:len({(k/l)for(k,l)in(zip(*map(sorted,[[sum((t[m][x][n]-t[m][x-1][n])**2for(n)in(0,1))for(x)in(0,1,2)]for(m)in(0,1)])))})==1

June 15, 2022

Comments:

dankiktenko on June 15, 2022, 7:39 a.m.
If you'd like <pre class='brush: python'>sum(t[m][x+i][n]*(~i-i)for(i)in(-1,0)) </pre> Instead of <pre class='brush: python'>t[m][x][n]-t[m][x-1][n] </pre> Makes code even more readable because there's no copy-paste fragments anymore, what is a known good programming practice.

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