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First solution in Clear category for Similar Triangles by atikin88
from typing import List, Tuple
Coords = List[Tuple[int, int]]
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
#getting sorted length os triangle's sides
foo = sorted ([((coords_1[i][0] - coords_1[i-1][0])**2 +
(coords_1[i][1] - coords_1[i-1][1])**2)**0.5 for i in range(3) ])
bar = sorted ([((coords_2[i][0] - coords_2[i-1][0])**2 +
(coords_2[i][1] - coords_2[i-1][1])**2)**0.5 for i in range(3) ])
#compare sides
compare = [foo[i]/bar[i] for i in range(3)]
#print('\n',foo,'\n',bar,'\n',compare)
if len(set(compare)) == 1:
return True
return False
if __name__ == '__main__':
print("Example:")
print(similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]))
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
Feb. 14, 2020
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