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Second solution in Clear category for Second Index by zaviskapavel
def second_index(text: str, symbol: str) -> [int, None]:
"""
returns the second index of a symbol in a given text
"""
return None if text.count(symbol) < 2 else text.find(symbol, text.find(symbol)+1)
if __name__ == '__main__':
print('Example:')
print(second_index("sims", "s"))
# These "asserts" are used for self-checking and not for an auto-testing
assert second_index("sims", "s") == 3, "First"
assert second_index("find the river", "e") == 12, "Second"
assert second_index("hi", " ") is None, "Third"
assert second_index("hi mayor", " ") is None, "Fourth"
assert second_index("hi mr Mayor", " ") == 5, "Fifth"
print('You are awesome! All tests are done! Go Check it!')
Nov. 29, 2018
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