Enhanced speedy solution for Second Index by Ylliw - python coding challenges - Py.CheckiO

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Enhanced solution in Speedy category for Second Index by Ylliw

d=lambda x:x if x>0 else None
second_index=lambda t,s:d(t.find(s,t.find(s)+1))

Dec. 7, 2017

Comments:

big_h_chicken on May 18, 2019, 2:42 p.m.
<p>nice</p>

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