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Readable solution in Clear category for Second Index by X-Yupto10
def second_index(text: str, symbol: str) -> [int, None]:
"""
returns the second index of a symbol in a given text
"""
second_occurence = text.find(symbol, text.find(symbol)+1)
if text.count(symbol) > 1:
return second_occurence
else:
return None
if __name__ == '__main__':
print('Example:')
print(second_index("sims", "s"))
# These "asserts" are used for self-checking and not for an auto-testing
assert second_index("sims", "s") == 3, "First"
assert second_index("find the river", "e") == 12, "Second"
assert second_index("hi", " ") is None, "Third"
assert second_index("hi mayor", " ") is None, "Fourth"
assert second_index("hi mr Mayor", " ") == 5, "Fifth"
print('You are awesome! All tests are done! Go Check it!')
April 26, 2021
