First clear solution for Second Index by StanislauL - python coding challenges

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First solution in Clear category for Second Index by StanislauL

def second_index(text: str, symbol: str):
    num = text.find(symbol, text.find(symbol)+1)
    return num if num>-1 else None

Jan. 20, 2018

Comments:

Duomim on Oct. 16, 2018, 2:38 p.m.
def second_index(char1 :str, char2: str) -> [int,None]: <pre class='brush: python'>num = char1.find(char2) # 字符的方法可以不指定结束范围,所以len(char1)可以节省 num2 = char1.find(char2,num+1) # num2 = char1.find(char2,num+1,len(char1)) return None if num == -1 or num2 ==-1 else num2 </pre> 这是我之前写的代码我不知道为什么num==-1可以不要,看了你的代码明白了,如果第一次没有找到,num 是-1,-1+1 = 0,又是从0开始找,所以可以不要.哈哈,Tankyou

LuisV_4ed4dd38f49c4f67b0a568dd on Aug. 27, 2020, 11:16 a.m.
Yes, I much prefer this to the alternative (using index() and catching the exception if it throws).

cjqtiger on May 29, 2023, 1 p.m.
nice

Strings Theory

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