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First solution in Clear category for Roman Numerals by palanevich.aleksey
def checkio(data):
thousand, hundred = divmod(data, 1000)
hundred, decade = divmod(hundred, 100)
decade, unit = divmod(decade, 10)
T = ('', 'M', 'MM', 'MMM')
H = ('', 'C', 'CC', 'CCC', 'CD', 'D', 'DC', 'DCC', 'DCCC', 'CM')
D = ('', 'X', 'XX', 'XXX', 'XL', 'L', 'LX', 'LXX', 'LXXX', 'XC')
U = ('', 'I', 'II', 'III', 'IV', 'V', 'VI', 'VII', 'VIII', 'IX')
return T[thousand] + H[hundred] + D[decade] + U[unit]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
print('Done! Go Check!')
Oct. 29, 2019
