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First solution in Clear category for Roman Numerals by koyana222
def checkio(data):
digit_0 = {0:"",1:"I",2:"II",3:"III",4:"IV",5:"V",6:"VI",7:"VII",8:"VIII",9:"IX"}
digit_1 = {0:"",1:"X",2:"XX",3:"XXX",4:"XL",5:"L",6:"LX",7:"LXX",8:"LXXX",9:"XC"}
digit_2 = {0:"",1:"C",2:"CC",3:"CCC",4:"CD",5:"D",6:"DC",7:"DCC",8:"DCCC",9:"CM"}
digit_3 = {0:"",1:"M",2:"MM",3:"MMM"}
roman_list = [digit_0,digit_1,digit_2,digit_3]
num_list = []
for i in range(0,len(str(data))):
num_list.append(roman_list[len(str(data))-1-i][int(str(data)[i])])
result = "".join(num_list)
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
print('Done! Go Check!')
April 9, 2019
