Thanks stackoverflow speedy solution for Roman Numerals by Stensen - python coding challenges

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Thanks stackoverflow solution in Speedy category for Roman Numerals by Stensen

rep = [["I"*5, "V"], ["V"*2, "X"], ["X"*5, "L"], ["L"*2, "C"],
      ["C"*5, "D"], ["D"*2, "M"], ["DCCCC", "CM"], ["CCCC", "CD"],
      ["LXXXX", "XC"], ["XXXX", "XL"], ["VIIII", "IX"], ["IIII", "IV"]]
def checkio(data):
    st = "I"*data
    for r in rep: st = st.replace(*r);
    return st;

Sept. 23, 2020

Comments:

SasuH on Jan. 19, 2021, 2:01 p.m.
<p>Clever!</p>

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