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First solution in Clear category for Roman Numerals by JulianNicholls
elements = { 1000 : 'M', 900 : 'CM', 500 : 'D', 400 : 'CD',
100 : 'C', 90 : 'XC', 50 : 'L', 40: 'XL',
10 : 'X', 9 : 'IX', 5 : 'V', 4: 'IV', 1 : 'I' }
def checkio(data):
roman = ''
for n in sorted(elements.keys(), reverse=True):
while data >= n:
roman += elements[n]
data -= n
return roman
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
Feb. 15, 2014
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