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First solution in Clear category for Roman Numerals by ForrestGump
def checkio(data):
ints = (1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1)
nums = ('M', 'CM', 'D', 'CD', 'C', 'XC',
'L', 'XL', 'X', 'IX', 'V', 'IV', 'I')
result = []
for i in range(len(ints)):
count = int(data / ints[i])
result.append(nums[i] * count)
data -= ints[i] * count
return ''.join(result)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
Sept. 5, 2014
