First clear solution for Right to Left by nishiura - python coding challenges

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First solution in Clear category for Right to Left by nishiura

def left_join(phrases: tuple) -> str:
    """
    Join strings and replace "right" to "left"
    """
    sentence = ''
    for word in phrases:
        sentence += (word+',')
    
    sentence = sentence[:-1]
    
    return sentence.replace('right', 'left')


if __name__ == "__main__":
    print("Example:")
    print(left_join(("left", "right", "left", "stop")))

    # These "asserts" using only for self-checking and not necessary for auto-testing
    assert (
        left_join(("left", "right", "left", "stop")) == "left,left,left,stop"
    ), "All to left"
    assert left_join(("bright aright", "ok")) == "bleft aleft,ok", "Bright Left"
    assert left_join(("brightness wright",)) == "bleftness wleft", "One phrase"
    assert left_join(("enough", "jokes")) == "enough,jokes", "Nothing to replace"
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

May 14, 2022

Comments:

hbczmxy on Oct. 3, 2022, 2:22 a.m.
Your solution is great! But I have some little advise about your code. I think you can use `enumerate` built-in function to recognize whether the `word` is the last part of `phrases`, then change the last for-loop statement. For example: <pre class='brush: python'>sentence = "" for counter, word in enumerate(prases, 1): sentence += (word + ',') if counter <= len(phrases) else word return sentence.replace('right', 'left') </pre>

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