yield from reversed(ascending list) clear solution for Reverse Every Ascending by Phil15 - python coding challenges

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yield from reversed(ascending list) solution in Clear category for Reverse Every Ascending by Phil15

#to_list = lambda f: lambda *args, **kwargs: list(f(*args, **kwargs))

#@to_list # Outputs doesn't have to be lists in "Check" tests.
def reverse_ascending(iterable):
    ascending = []
    for elem in iterable:
        if ascending and ascending[-1] >= elem:
            yield from reversed(ascending)
            ascending = []
        ascending.append(elem)
    yield from reversed(ascending)

Dec. 5, 2018

Comments:

jakubbortlik on Dec. 27, 2022, 7:26 a.m.
Nice solution. An alternative for lines 8-9 that I find slightly more elegant is: ``` while ascending: yield ascending.pop() ```

Phil15 on Dec. 27, 2022, 8 a.m.
`reversed` returning a generator in a "yield from" context seemed elegant to me but that works too. I also thought of `ascending.clear()` instead of `ascending = []`.

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