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Iterate copy of list and remove first instance of value if not equal to border solution in Clear category for Remove All Before by Kemeros
from typing import Iterable
def remove_all_before(items: list, border: int) -> Iterable:
if border in items:
for i in items.copy():
if i != border:
items.remove(i)
else:
return items
else:
return items
if __name__ == '__main__':
print("Example:")
print(list(remove_all_before([1, 2, 3, 4, 5], 3)))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(remove_all_before([1, 2, 3, 4, 5], 3)) == [3, 4, 5]
assert list(remove_all_before([1, 1, 2, 2, 3, 3], 2)) == [2, 2, 3, 3]
assert list(remove_all_before([1, 1, 2, 4, 2, 3, 4], 2)) == [2, 4, 2, 3, 4]
assert list(remove_all_before([1, 1, 5, 6, 7], 2)) == [1, 1, 5, 6, 7]
assert list(remove_all_before([], 0)) == []
assert list(remove_all_before([7, 7, 7, 7, 7, 7, 7, 7, 7], 7)) == [7, 7, 7, 7, 7, 7, 7, 7, 7]
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Jan. 29, 2021
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