First creative solution for Radiation Search by rick.felsing - python coding challenges

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First solution in Creative category for Radiation Search by rick.felsing

def checkio(m):
    l = len(m)
    v = [[False for i in range(l)] for i in range(l)]
    def c(x, y, n):        
        if not 0<=x
                        May 23, 2015

                        
                            Comments:
                            
                                
                                    rick.felsing
 on May 23, 2015, 12:16 a.m.

                                    <p>Perhaps easier to understand in this format:</p>

<p>def checkio(matrix):
    ln = len(matrix)
    visited = [[False for i in range(ln)] for i in range(ln)]
    def count(x, y, num): <br />
        if not 0 &lt;= x &lt; ln or not 0 &lt;= y &lt; ln:
            return 0
        if visited[x][y]:
            return 0
        if matrix[x][y] == num:
            visited[x][y] = True
            quan = 1
            quan += count(x + 1, y)
            quan += count(x - 1, y)
            quan += count(x, y + 1)
            quan += count(x, y - 1)
            return quan
        return 0 <br />
    return max([count(x, y, matrix[x][y]), matrix[x][y]] for x in range(ln) for y in range(ln))</p>

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