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First solution in Clear category for Probably Dice by brownie57
def probability(dice_number, sides, target):
dict1 = {i:1 for i in range(1, sides + 1)}
for x in range(dice_number - 1):
dict2 = {}
for i in dict1.keys():
for j in range(1, sides + 1):
dict2.setdefault(i + j, 0)
dict2[i + j] += dict1[i]
dict1 = dict2
return round(dict1.get(target, 0) / sides ** dice_number, 4)
if __name__ == '__main__':
#These are only used for self-checking and are not necessary for auto-testing
def almost_equal(checked, correct, significant_digits=4):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert(almost_equal(probability(2, 6, 3), 0.0556)), "Basic example"
assert(almost_equal(probability(2, 6, 4), 0.0833)), "More points"
assert(almost_equal(probability(2, 6, 7), 0.1667)), "Maximum for two 6-sided dice"
assert(almost_equal(probability(2, 3, 5), 0.2222)), "Small dice"
assert(almost_equal(probability(2, 3, 7), 0.0000)), "Never!"
assert(almost_equal(probability(3, 6, 7), 0.0694)), "Three dice"
assert(almost_equal(probability(10, 10, 50), 0.0375)), "Many dice, many sides"
Dec. 5, 2018
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