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Smart brute force solution in Clear category for Probably Dice by Vasily__Chibilyaev
def probability(dice_number, sides, target):
from itertools import product
res={a: 1 for a in range(1, sides+1)}
for i in range(1, dice_number):
tmp={}
for a, b in product(res.keys(), range(1, sides+1)):
if a+b in tmp:
tmp[a+b]+=res[a]
else:
tmp[a+b]=res[a]
res=tmp
return res[target]/sides**dice_number if target in res else 0
if __name__ == '__main__':
#These are only used for self-checking and are not necessary for auto-testing
def almost_equal(checked, correct, significant_digits=4):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert(almost_equal(probability(2, 6, 3), 0.0556)), "Basic example"
assert(almost_equal(probability(2, 6, 4), 0.0833)), "More points"
assert(almost_equal(probability(2, 6, 7), 0.1667)), "Maximum for two 6-sided dice"
assert(almost_equal(probability(2, 3, 5), 0.2222)), "Small dice"
assert(almost_equal(probability(2, 3, 7), 0.0000)), "Never!"
assert(almost_equal(probability(3, 6, 7), 0.0694)), "Three dice"
assert(almost_equal(probability(10, 10, 50), 0.0375)), "Many dice, many sides"
Sept. 29, 2017
