First clear solution for Popular Words by kim.yangjin - python coding challenges

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First solution in Clear category for Popular Words by kim.yangjin

def popular_words(text: str, words: list) -> dict:
    result = {}
    for i in words:
        result[i] = text.lower().split().count(i)
    return result

May 7, 2020

Comments:

undead2k on Aug. 2, 2020, 6:37 p.m.
<p>I would never had imagined `result[i] = text.lower().split().count(i)` would work. Did not know you could do that to dictionaries :D </p> <p>Inspired by your code, I figured out how to do it as a one-liner, using dictionary comprehension; </p> <pre class='brush: python'>def popular_words(text: str, words: list) -> dict: return {i : text.lower().split().count(i) for i in words} </pre>

Look up in the Dict()

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