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Concise algorithm solution in Speedy category for Popular Words by Igor_Sekretarev
from collections import Counter
def popular_words(text: str, words: list) -> dict:
count = Counter(text.lower().split())
return {word:count[word] for word in words}
if __name__ == '__main__':
print("Example:")
print(popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']))
# These "asserts" are used for self-checking and not for an auto-testing
assert popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']) == {
'i': 4,
'was': 3,
'three': 0,
'near': 0
}
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April 24, 2021
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