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First solution in Clear category for Pawn Brotherhood by wojtekpaciej
import string
LETTERS = string.ascii_lowercase
def safe_pawns(pawns):
pawn_coords = []
count=0
for pair in pawns:
x = LETTERS.index(pair[0]) + 1
pawn_coords.append((x,int(pair[1])))
for row, col in pawn_coords:
is_safe = (row - 1, col -1) in pawn_coords or (row + 1, col - 1) in pawn_coords
if is_safe:
count +=1
print(count)
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Dec. 12, 2016
