First clear solution for Pawn Brotherhood by tmaeda11235 - python coding challenges

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First solution in Clear category for Pawn Brotherhood by tmaeda11235

def safe_pawns(pawns):
    safe_area = set()
    for pawn in pawns:
        col, row = map(ord, pawn)
        safe_area |= {"".join(map(chr, (col + 1, row + 1)))}
        safe_area |= {"".join(map(chr, (col - 1, row + 1)))}
    return len(safe_area & pawns)

Aug. 12, 2017

Look up in the Dict()

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