First clear solution for Pawn Brotherhood by sts10131 - python coding challenges

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First solution in Clear category for Pawn Brotherhood by sts10131

def safe_pawns(pawns):
    safe=0;
    for x in pawns:
        for y in pawns:
            if (ord(y[0])-1==ord(x[0]) or ord(y[0])+1==ord(x[0])) and ord(y[1])+1==ord(x[1]):              
                safe+=1
                break
    return safe

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Dec. 27, 2016

Look up in the Dict()

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