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How I did it solution in Clear category for Pawn Brotherhood by rettrus
def safe_pawns(pawns: set) -> int:
counter = 0 # The number of safe pawns as a integer
for c in pawns:
def1 = chr((ord(c[0]) - 1)) + str(int(c[1]) - 1) # define the 1st possible defender coordinates
def2 = chr((ord(c[0]) + 1)) + str(int(c[1]) - 1) # define the 2nd possible defender coordinates
if def1 in pawns or def2 in pawns: # if one of the possible defenders is in list we count up
counter += 1 # count up
return counter
if __name__ == '__main__':
print("Example:")
print(safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
April 28, 2021
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