Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
isdisjoint solution in Clear category for Pawn Brotherhood by r_tchaik
def guards(pawn):
return {chr((x := ord(pawn[0])) - 1) + (y := str(int(pawn[1]) - 1)), chr(x + 1) + y}
def safe_pawns(pawns: set) -> int:
return sum(not guards(pawn).isdisjoint(pawns) for pawn in pawns)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
July 25, 2020
