7 clear lines of code clear solution for Pawn Brotherhood by pawel1337 - python coding challenges

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7 clear lines of code solution in Clear category for Pawn Brotherhood by pawel1337

def safe_pawns(pawns):
    num = 0
    for pawn in pawns:
        op1 = (chr(ord(pawn[0]) - 1)) + (chr(ord(pawn[1]) - 1))
        op2 = (chr(ord(pawn[0]) + 1)) + (chr(ord(pawn[1]) - 1))
        if (op1 in pawns) or (op2 in pawns):
            num += 1
    return num

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Nov. 3, 2016

Look up in the Dict()

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