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Count 'em all solution in Clear category for Pawn Brotherhood by obone
def safer(p, left=True):
return chr(ord(p[0]) - (1 if left else -1)) + chr(ord(p[1]) - 1)
def safe_pawns(pawns: set) -> int:
safe = 0
for p in pawns:
if safer(p) in pawns or safer(p, False) in pawns:
safe += 1
return safe
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
June 8, 2019
