One liner creative solution for Pawn Brotherhood by oLeBeLo - python coding challenges - Py.CheckiO

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One liner solution in Creative category for Pawn Brotherhood by oLeBeLo

safe_pawns= lambda P: sum([chr(ord(p[0])-1)+chr(ord(p[1])-1) in P or \
                chr(ord(p[0])+1)+chr(ord(p[1])-1) in P for p in P])

Feb. 3, 2018

Look up in the Dict()

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