13 lines, for loop clear solution for Pawn Brotherhood by mickas - python coding challenges

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13 lines, for loop solution in Clear category for Pawn Brotherhood by mickas

def safe_pawns(pawns: set) -> int:
    safe = 0
    pawn_guard_L = ""
    pawn_guard_R = ""
    
    for pawn in pawns:
        pawn_guard_L = chr(ord(pawn[0]) - 1) + chr(ord(pawn[1]) - 1)
        pawn_guard_R = chr(ord(pawn[0]) + 1) + chr(ord(pawn[1]) - 1)
        
        if pawn_guard_L in pawns or pawn_guard_R in pawns:
            safe += 1
            
    return safe

July 6, 2020

Comments:

zwerkoff on July 28, 2020, 9:09 a.m.
<p>beautiful code</p>

Look up in the Dict()

0 %

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