First clear solution for Pawn Brotherhood by merlengross - python coding challenges

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First solution in Clear category for Pawn Brotherhood by merlengross

def safe_pawns(pawns):
    safe = 0
    
    for pawn in pawns:
        row = str(int(pawn[1]) - 1)
        left = chr(ord(pawn[0]) - 1) + row
        right = chr(ord(pawn[0]) + 1) + row
        
        if left in pawns or right in pawns:
            safe += 1
            
    return safe

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Dec. 20, 2014

Look up in the Dict()

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