First clear solution for Pawn Brotherhood by mateusz.miekus - python coding challenges

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First solution in Clear category for Pawn Brotherhood by mateusz.miekus

def safe_pawns(pawns):
    
    coords=[]
    for i in pawns:
        
        x= ord(i[0])
        coords.append(x)
        x= int(i[1])
        coords.append(x)
 
    i=0
    t=0
    
    while i< len(coords):
        k=0
        l=0
        while k=1:
            t+=1
        
        i+=2
        
    return t    
        
    
    
if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Oct. 29, 2016

Look up in the Dict()

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