Simple 7 Strings speedy solution for Pawn Brotherhood by masterspace.dc - python coding challenges

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Simple 7 Strings solution in Speedy category for Pawn Brotherhood by masterspace.dc

def safe_pawns(pawns):
    n=0
    for i in pawns:
        for j in pawns:
            if i!=j and (ord(i[0])==ord(j[0])+1 or ord(i[0])==ord(j[0])-1) and int(i[1])==int(j[1])+1:
                n+=1
                break
    return n

Nov. 1, 2017

Look up in the Dict()

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