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double loop solution in Clear category for Pawn Brotherhood by marcel.sliwinski
def safe_pawns(pawns):
ans=0
save=0
for i in pawns:
for j in pawns:
if (int(i[1])==int(j[1])+1 and (ord(i[0])==ord(j[0])-1 or ord(i[0])==ord(j[0])+1)):
if (i!=save):
ans=ans+1
save=i
return ans
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Feb. 23, 2017