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First solution in Clear category for Pawn Brotherhood by koyana222
def safe_pawns(pawns: set) -> int:
pawns_list = list(pawns)
alfabet_list = ["x","a","b","c","d","e","f","g","h","i"]
count = 0
for i in pawns_list:
check_left = alfabet_list[alfabet_list.index(i[0])-1] + str(int(i[1])-1)
check_right = alfabet_list[alfabet_list.index(i[0])+1] + str(int(i[1])-1)
if check_left in pawns_list or check_right in pawns_list:
count += 1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Feb. 17, 2019
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