First clear solution for Pawn Brotherhood by imhuwq - python coding challenges

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First solution in Clear category for Pawn Brotherhood by imhuwq

def safe_pawns(pawns):
    count = 0
    for pawn in pawns:
        brothers = {'%s%s' % (chr(ord(pawn[0]) + 1), int(pawn[1]) - 1),
                    '%s%s' % (chr(ord(pawn[0]) - 1), int(pawn[1]) - 1)}

        if brothers & pawns:
            count += 1

    return count


if __name__ == '__main__':
    # These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

May 31, 2016

Look up in the Dict()

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