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First solution in 3rd party category for Pawn Brotherhood by faleon
import numpy as np
def safe_pawns(pawns):
dict = {'a':0, 'b':1, 'c':2, 'd':3, 'e':4, 'f':5, 'g':6, 'h':7}
tablero = np.zeros((8,8))
for coord in pawns:
i= 8 - int(coord[1])
j=dict[coord[0]]
tablero[i,j]=1
f,c =tablero.shape
cont =0
for i in range(f):
for j in range (c):
if tablero[i,j] ==1:
if tablero[i +1:i+2,j-1:j]== 1 or tablero[i + 1:i + 2, j+1:j+2]==1:
cont += 1
return cont
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Jan. 19, 2017
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