First clear solution for Pawn Brotherhood by dominikbrandon - python coding challenges

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First solution in Clear category for Pawn Brotherhood by dominikbrandon

def safe_pawns(pawns):
    array = ["z","a","b","c","d","e","f","g","h","z"]
    counter = 0
    for row in range(2, 9):
        for column in range(1, 9):
            if (array[column] + str(row)) in pawns:
                if (array[column - 1] + str(row - 1)) in pawns:
                    counter += 1
                elif (array[column + 1] + str(row - 1)) in pawns:
                    counter += 1
            column += 1
        row += 1
    return counter

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Oct. 17, 2016

Look up in the Dict()

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