First clear solution for Pawn Brotherhood by cinekk - python coding challenges

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First solution in Clear category for Pawn Brotherhood by cinekk

def safe_pawns(pawns):
    safe_ones = 0
    
    for el in pawns:
        letter = el[0]
        number = int(el[1])
        for tmp in pawns:
            if ord(letter) == ord(tmp[0])-1 or ord(letter) == ord(tmp[0])+1:
                if number == int(tmp[1])+1:
                    safe_ones += 1
                    break
            
    return safe_ones


if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Oct. 19, 2016

Look up in the Dict()

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