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2-liner: The Fastest & Clearest solution in Clear category for Pawn Brotherhood by assargin
def safe_pawns(pawns: set) -> int:
# set of tuples (quick search!) with digital coords (1-8 for a-h)
pos = {(ord(p[0])-96, int(p[1])) for p in pawns}
# for every pawn check at least one defender pawns exists
return len([1 for col, row in pos if (col-1, row-1) in pos or (col+1, row-1) in pos])
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Feb. 10, 2020
